Pair of linear equations in two variables
Standard Equations of Linear Equations – a1x + b1y + c1 = 0
a2x + b2y + c2 = 0
Linear equations a1x + b1y + c1 = 0 and a2x + b2y + c2 = 0 represents a pair of linear equations that can lead to the following situations.
| Linear Equations | Comparison of Ratios | Graphical Solution | Algebraic Solution | Consistent/Inconsistent |
| a1x + b1y + c1 = 0 | a1 = b1 = c1 | Coincident lines | Multiple solutions | consistent solution |
| a2x + b2y + c2 = 0 | a2 b2 c2 | (dependent) | ||
| a1x + b1x + c1 = 0 | a1 = b1 | Parallel lines | No solution | inconsistent solution |
| a2x + b2x + c2 = 0 | a2 b2 c2 | |||
| a1x + b1x + c1 = 0 | a1 | Intersecting lines | Unique (one) solution | consistent solution |
| a2x + b2x + c2 = 0 | a2 b2 c2 | |||

Exercise – 3.1
Q. 1. Form the pair of linear equations for the following problems and find their solutions graphically.
(i) 10 students of Class X took part in a mathematics quiz. If the number of girls is 4 more than the number of boys, find the number of boys and girls who took part in the quiz.
1. Total students = 10
Let the number of girls = x
Let the number of boys = y
According to the question,
x = y + 4 _ _ _ 1
x + y = 10 _ _ _ 2
From equation 1,
x = y + 4 = Let y = 1 = Let y = 2
Let [y = 0] x = 1 + 4 x = 2 + 4
x = 0 + 4 [ x = 5 ] [ x = 6 ]
| x | 4 | 5 | 6 |
| y | 0 | 1 | 2 |
From equation 2,
x + y =10 = Let y = 1 = Let y = 2
Let y = 10 x + 1 = 10 x + 2 = 10
x + 0 = 10 x = 10 – 1 x = 10 – 2
[ x = 10 ] [ x = 9 ] [ x = 8 ]
| x | 10 | 9 | 8 |
| y | 0 | 1 | 2 |
X = 7 , y = 3
Number of girls = 7
Number of boys = 3
(ii) The total cost of 5 pencils and 7 pens is ₹50, while the total cost of 7 pencils and 5 pens is ₹46. Find the cost of one pencil and the cost of one pen.
Let the price of 1 pencil = Rs. x
Let the price of 1 pen = Rs. y
According to the question,
5x + 7y = 50 _ _ _ _ 1
7x + 5y = 46 _ _ _ _ 2
From equation 1,
5x + 7y = 50
5x = 50 – 7y

| x | 10 | 3 | -4 |
| y | 0 | 5 | 10 |
From Equation 2,
7x + 5y = 46
5y = 46 – 7x

| x | 0 | 5 | 10 |
| y | 9.2 | 2.2 | -4.8 |
Price of a pencil ( x ) = ₹3
Price of a pen ( y ) = ₹5
Q. 2. By comparing the ratios, determine whether the lines represented by the following pair of equations intersect at a point, are parallel, or are coincident:
1. 5x – 4y + 8 = 0
7x + 6y – 9 = 0
a1x + b1y + c1 = 0
a2x + b2y + c2 = 0
a1 = 5 , b1 = -4 , c1 = 8
a2 = 7 , b2 = 6 , c2 = -9

So these are intersecting lines.
2. 9x + 3y + 12 = 0
18x + 6y + 24 = 0
a1 = 9 , b1 = 3 , c1 = 12
a2 = 18 , b2 = 6 , c2 = 24

So these are coincident lines.
3. 6x – 3y + 10 = 0
2x – y + 9 = 0
a1 = 6 , b1 = – 3 , c1 = 10
a2 = 2 , b2 = – 1 , c2 = 9

So these are parallel lines.
Q. 3. By comparing the ratios, determine whether the following pairs of linear equations are consistent or inconsistent.
1. 3x + 2y = 5 ; 2x – 3y = 7
3x + 2y – 5 = 0 ; 2x – 3y – 7 = 0
a1x + b1y + c1 = 0 ; a2x + b2y + c2 = 0

(Consistent solution)
2. 2x – 3y = 8 ; 4x – 6y = 9
2x – 3y – 8 = 0 ; 4x – 6y – x = 0
a1x + b1x + c1 = 0 ; a2x + b2x + c2 = 0
a1 = 2 , b1 = – 3 , c1 = – 8
a2 = 4 , b2 = – 6 , c2 = – 9

(Inconsistent solution)

4. 5x – 3y = 11 ; -10x + 6y = – 22
5x – 3y – 11 = 0 ; -10x + 6y + 22 = 0
a1x + b1y + c1 = 0 ; a2x + b2y + c2 = 0
a1 = 5 , b1 = 3 , c1 = 11
a2 = 10 , b2 = 6 , c2 = 22

Dependent (consistent) solution

Q. 4. Which of the following pairs of linear equations are consistent/inconsistent?
1. X + y = 5 , 2x + 2y = 10
X + y – 5 = 0 , 2x + 2y – 10 = 0
a1 = 1 , b1 = 1 , c1 = – 5
a2 = 2 , b2 = 2 , c2 = – 10

Dependent (consistent) solution
2. x – y = 8 , 3x – 3y = 16
X – y – 8 = 0 , 3x – 3y – 16 = 0
a1 = 1 , b1 = -1 , c1 = – 8
a2 = 3 , b2 = 3 , c2 = – 16

(Inconsistent solution)
3. 2x + y – 6 = 0 , 4x – 2y – 4 = 0
a1 = 2 , b1 = 1 , c1 = – 6
a2 = 4 , b2 = -2 , c2 = – 4

(Consistent solution)
4. 2x – 2y – 2 , 4x – 4y – 5 = 0
a1 = 2 , b1 = -2 , c1 = – 2
a2 = 4 , b2 = -4 , c2 = – 5

(Inconsistent solution)
Q. 5. The semi-perimeter of a rectangular garden, whose length is 4 m more than its width, is 36 m. Find the dimensions of the garden.
5. Let the length of the rectangular garden = x
Let the width of the rectangular garden = y
According to the question,
x = y + 4 -(1)
Semiperimeter = 36 m

x + y = 36
From Equation 1,
x = y + 4
Let y = 0
X = 0 + 4
X = 4
Let y = 1
X = 1 + 4
X = 5
Let y = 2
X = 2 + 4
X = 6
| x | 4 | 5 | 6 |
| y | 0 | 1 | 2 |
From Equation 2,,
X + y = 36
X = 36 – y
Let y = 10
X = 36 – 10
X = 26
Let y = 12
X = 36 – 12
X = 24
Let y = 14
X = 36 – 14
X = 22
| x | 26 | 24 | 22 |
| y | 10 | 12 | 14 |
X = 20
Y = 16
