Triangle Solutions

Triangle Solutions

Que. 1. In figures (i) and (ii), DE || BC. Find EC in (i) and AD in (ii):

Triangle Solutions

(i)

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(ii)

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Que. 2. Points E and F lie on the sides PQ and PR, respectively, of a triangle PQR. State whether EF || QR:

1. PE = 3.9 Cm, EQ = 3 Cm, PE = 3.6 Cm, PR = 2.4 Cm

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PE = 3.9 Cm

EQ = 3 Cm

PE = 3.6 Cm

PR = 2.4 Cm

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1.3 = 1.5

Hence, EF is not parallel to QR.

Que. 3. In the figure, if LM || CB and LN || CD, prove that AM/AB = AN/AD.

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Given – LM || BC

                LN || CD

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Que. 4. In the figure, DE || AC and DF || AE. Prove that BF/FE = BE/EC.

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Given – DE || AC

                DF || AE

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Que. 5. In the figure, DE || OQ and DF || OR. Show that EF || QR.

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Given – DE || OQ

                DF || OR

Proven – EF || QR

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Que. 6. In the figure, points A, B, and C lie on OP, OQ, and OR respectively, such that AB || PQ and AC || PR. Show that BC || QR.

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Given – AB || PQ

                AC || PR

Proven – BC || QR

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By the converse of Thales’ Theorem,

BC || QR

Que. 7.Using Theorem 6.1, prove that a line drawn through the midpoint of one side of a triangle parallel to another side bisects the third side.

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Given – AD = BD   ——(1)

                DE || BC

Proven – AE = EC

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CE = AE

Que. 8. Using Theorem 6.2, prove that the line joining the mid-points of any two sides of a triangle is parallel to the third side.

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Given – AD = BD

                AE = CE

Proven – DE || BC

AD = BD

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By the converse of Thales’ Theorem,

DE || BC

Que. 9. ABCD is a trapezium in which AB || DC, and its diagonals intersect each other at point O. Show that AO/BO = CO/DO.

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Given – ABCD is a trapezium.

                 AB || CD

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Que. 10. The diagonals of a quadrilateral ABCD intersect each other at point O such that AO/BO = CO/DO. Show that ABCD is a trapezium.

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By the converse of Thales’ Theorem,

OE || CD

Therefore, AB || CD.

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